We can perform a targeted analysis to identify patterns and trends. To isolate the data pertinent to our analysis, we must filter rows based on conditions from a data frame. Conditions help us uncover patterns and trends within our data.
Here are the two most prominent ways to select rows by single or multiple conditions in R:
Subsetting with a square bracket ([ ]) is a basic way to select rows where the column meets the condition. For example, df[df$column_name > value, ].
Here is the input data frame we will use throughout this tutorial:
df <- data.frame(
name = c("Millie", "Yogita", "KMJ"),
score = c(90, 95, 77),
subject = c("Biology", "Biology", "Biology"),
grade = c(12, 12, 11)
)
Let’s apply a single condition to filter rows using subsetting.
Fetch me the rows where ‘score’ > 85.
df <- data.frame(
name = c("Millie", "Yogita", "KMJ"),
score = c(90, 95, 77),
subject = c("Biology", "Biology", "Biology"),
grade = c(12, 12, 11)
)
df[df$score > 85, ]
Our central column to filter is “score”, and you can select any column of the data frame using the “df$score” syntax, which we have done. For filtering, we used a greater than (>) sign to select only columns with scores greater than 85.
To apply multiple conditions at once, you can use the And (&)/Or (|) operator. But make sure to use the vector logical operators & and |, not the scalar ones && or ||.
Let’s select only rows whose score is > 70 & grade == 11.
df <- data.frame(
name = c("Millie", "Yogita", "KMJ"),
score = c(90, 95, 77),
subject = c("Biology", "Biology", "Biology"),
grade = c(12, 12, 11)
)
df[df$score > 70 & df$grade == 11, ]
After filtering, only row number 3 satisfied our conditions, so we got that in the output, as shown in the above figure.
If there are NAs in the column, the condition might result in NA, which would be treated as FALSE in subsetting. Using a function like is.na(), we can check for any NA values before subsetting on it.
Although our data frame does not contain any NA values, we can use a different data frame that contains NA values.
df <- data.frame(
name = c("Millie", "Yogita", NA),
score = c(90, 95, NA),
subject = c("Biology", "Biology", "Biology"),
grade = c(12, 12, 11)
)
df[is.na(df$score) | df$age > 70, ]
[1] name score subject grade
<0 rows> (or 0-length row.names)
Since our data frame, df contains NA values, we get the 0 rows in the output.
Let’s select rows based on specific string column values using the “grepl()” function.
df <- data.frame(
name = c("Millie", "Yogita", "KMJ"),
score = c(90, 95, 77),
subject = c("Biology", "Biology", "Biology"),
grade = c(12, 12, 11)
)
df[grepl("gita", df$name), ]
The dplyr filter() function subsets a data frame, retaining all rows that satisfy your conditions. For example df %>% filter(column_name > value).
The dplyr is a third-party package, so we need to install and load it in our program:
install.packages("dplyr")
library(dplyr)
Let’s select rows whose score is > 80 using the df %>% filter() function.
library(dplyr)
df <- data.frame(
name = c("Millie", "Yogita", "KMJ"),
score = c(90, 95, 77),
subject = c("Biology", "Biology", "Biology"),
grade = c(12, 12, 11)
)
df %>% filter(score > 80)
For multiple conditions, we can use: df %>% filter(first_column > value1, second_column == “value2”) or use “&” between conditions.
library(dplyr)
df <- data.frame(
name = c("Millie", "Yogita", "KMJ"),
score = c(90, 95, 77),
subject = c("Biology", "Biology", "Biology"),
grade = c(12, 12, 11)
)
df %>% filter(score > 70 & grade == 11)
Both methods provide flexibility; you can choose whichever method is based on your workflow and readability needs.
Krunal Lathiya is a seasoned Computer Science expert with over eight years in the tech industry. He boasts deep knowledge in Data Science and Machine Learning. Versed in Python, JavaScript, PHP, R, and Golang. Skilled in frameworks like Angular and React and platforms such as Node.js. His expertise spans both front-end and back-end development. His proficiency in the Python language stands as a testament to his versatility and commitment to the craft.
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